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Auto reload your Go webserver with Gulp

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2019-09-20

Categories: DevOps Programming

When you developp a webserver with Go, you must compile each time you do an update in your code. Well.. this is redundant. With Gulp you can automatize this task… Indeed, when a go file is modified, a task compile the application in the “bin” folder (“gopath/bin”) then another launch the executable (the webserver).

https://medium.com/@etiennerouzeaud/autoreload-your-go-webserver-with-gulp-ee5e231d133d

 1const gulp     = require('gulp'),
 2      util     = require('gulp-util'),
 3      notifier = require('node-notifier'),
 4      child    = require('child_process'),
 5      os       = require('os'),
 6      path     = require('path');
 7
 8var server = 'null'
 9
10function build() {
11    var build = child.spawn('go', ['install']);
12
13    build.stdout.on('data', (data) => {
14        console.log(`stdout: ${data}`);
15    });
16
17    build.stderr.on('data', (data) => {
18        console.error(`stderr: ${data}`);
19    });
20
21    return build;
22}
23
24function spawn(done) {
25    if (server && server != 'null') {
26        server.kill();
27    }
28
29    var path_folder = process.cwd().split(path.sep)
30    var length = path_folder.length
31    var app = path_folder[length - parseInt(1)];
32
33    if (os.platform() == 'win32') {
34        server = child.spawn(app + '.exe')
35    } else {
36        server = child.spawn(app)
37    }
38
39    server.stdout.on('data', (data) => {
40        console.log(`stdout: ${data}`);
41    });
42
43    server.stderr.on('data', (data) => {
44        console.log(`stderr: ${data}`);
45    });
46
47    done();
48}
49
50const serve = gulp.series(build, spawn)
51function watch(done) {
52    gulp.watch(['*.go', '**/*.go'], serve);
53    done();
54}
55
56exports.serve = serve
57exports.watch = watch
58exports.default = gulp.parallel(serve, watch)

Tags: web gulp

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